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Everything posted by ItsSC
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In case if someone got ban from team and want to create a new account. Here is the tips i use. 1. Create a new emulator / Use another phone to download the game. 2. Play the game and when u finish the tutorial, connect the new account with your banned google account. 3. Uninstall the game from your banned device,, or simply just remove data, then redownload and at the loading screen select "Save progress", choose the google account you used just now. 4. Enter the game, you will still sticked to the banned account, but the game will ask you to choose which account to use (New or banned). Choose the banned one and type in "Confirm". 5. Now you have a new fresh account.
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I think don't goes over 1000 items or you'll be ban from joining team. (I got ban from joining team when i holding 2000 items, dont be greedy haha)
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Welp, 20hours and your message finally reached to us. This is the weirdest situation i had never met before, does restarting GG works? It may because of lagging or crash causing the menu didn't shown up.
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I guess he might be looking for a script with those feature he mentioned?
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Elona mobile is still under early access. But stellar hunter has only 3.5 rating on play store and 800+ people follow on facebook, yet Elona has 3000+ people follow onfacebook. SO I guess Elona mobile is more popular. Maybe the game looks like Stardew Valley, so that's more on my preference haha.
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Stellar hunter, elona mobile. New protection again.
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I guess the reason they abandoned the game because they used to add a new event / item and cause the game extremely pay to win, and every rich guy in game started anti the game, eventually all of them quit the game. So they move on to create another money sucker game.
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The game hasn't patch the hack yet, so everything still works like in the video. Maybe you forgot to switch your equipment/ attachment after swapping coin with gold. (also don't forget to restart) The dev had stopped updating the game since 8 months ago... but they do create a new server on china, so maybe they abandoned international version.
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The answer is blue, because 3+5 not equal to orange.
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local search = gg.prompt({"Value to search"}, {}, {"value"}) gg.searchNumber(search[1], 4) -- [[Try shrink down your results here]] local res = gg.getResults(gg.getResultsCount()) for key, value in pairs(res)do value['value'] = -value['value'] end I don't think there is a need to use two prompt.. One prompt is fine. By the way, if you ar esearching for a "shop" item, I believe the price is fixed, so there's no need to use prompt actually, just search for the price by storing every item's price into a table. Call them out when user want the particular item. That is more user-friendly.
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Things you should know before understanding how everything works. There are four major number systems. 1. Binary 2. Octal 3. Decimal 4. Hexadecimal Range Binary system consist of 0 and 1 only. Octal system consist of 0 to 7 only. Decimal consist of 0 to 9 only. Hexadecimal includes 0 to 9 and A, B, C, D, E, F. Programming syntax (PART THAT YOU GET CONFUSED) Every programming has a special syntax for programmers to code whatever number system they want. Since we are using Lua, we focus on Lua syntax.If you want to print out 30 in decimal, you use print(30). But if you want to print 30 in decimal from hexadecimal, you use print(0x1e). 0x1e: 0x indicates this number is in hexadecimal, 1e means 30 in decimal. Now, look back to what you get from game guardian, offset :70. The 70 is in hexadecimal, so it works when you write 0x70 or 112. Also, 0xC not equal to 0x12, but 0xC equal to 12.
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function incrementSearch(startIndex, range) local INITIAL = 1 local INCREMENT = 1 local SLEEP_TIME = 50 for i = INITIAL, range do gg.searchNumber(startIndex, gg.TYPE_DWORD) startIndex = startIndex + INCREMENT end gg.sleep(SLEEP_TIME) -- Manipulate yourself end --usage incrementSearch(100,100);
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function toHexStringBigEndian(val) local hex = ""; local HEX_DIGIT_PATTERN = "%08x"; local MAGIC_CHARACTER = ".." string.gsub(string.format(HEX_DIGIT_PATTERN, val):sub(-8),MAGIC_CHARACTER, function(x) hex = x .. hex end) return hex end Learn some string manipulation, it's fun to learn :). Search for "Regex".
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hahaha that is the best analog i have seen.
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I got no idea why downvote other's post for no reason. So I give you an upvote to make neutralize the reputation. They had explained, there's no point finding the "server sided" value. Look at this analog and you will understand.
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Maybe the calculation is wrong.. For example, as your script asked "Timer number" if timer = 5, it should be 5, am I right? Then in your script you do 60-5, it become 55. So it is something wrong. Just from my plain guess. you should do this timer = gg.prompt( {"TIMER NUMBER"},{""},{"number"}) if(timer[1]>=60)then time = 60-timer[1] else time = timer[1] end This means when the time is 60 seconds, it should return 0. If time is 55, it should return 55, but your current script will return 5.
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Bloxburg.lua The script is running fine, no err found. Maybe the method has been patched? Or maybe the hacking step is wrong.
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A little question, what your inf gonna do ? Why edit the same value over and over?
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you mean std::endl? If it then \n in lua.
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Is there a way to detect android version in lua script?
ItsSC replied to MarioRossi93i's question in Help
I guess what Enyby means is You can search "-1500000100" then do the offset, if you didn't get any result from "-1500000100". That's mean this phone is not android 10. Then do -170000500 So in this case, I prefer using my way can help in reducing time on guessing the android version of user. -
Is there a way to detect android version in lua script?
ItsSC replied to MarioRossi93i's question in Help
Short answer : Don't use the script if they don't trust it. Just code, they don't want use then let them be. There is no point to think so much for them. If some script writer really want to do something malicious, disagree access internet wouldn't stop them. -
Is there a way to detect android version in lua script?
ItsSC replied to MarioRossi93i's question in Help
The solution was in documentation... There's no need to add new syntax , just print('GET 1: ', gg.makeRequest('http://httpbin.org/headers').content) -- simple GET request -
Wait... C++ is tougher than lua. At least you don't have to declare what type of the variable is For example C++: int a = 1; string b = "text"; char c = "A"; float d = 1.23; Meanwhile Lua: a = 1; b = "text"; c = "A"; d = 1.23;
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Short answer, don't use if you don't trust the application.