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For the text search, is it possible to increase group search range?

@NoFear I need help finding the equivalent value of the price of the stabilizer, any clues? Tried 10900 and even increasing group search range to 65535... none of the values that come up point to anything substantial

Might need to not do grouped. Maybe search price of just the 2000

You can buy them once with NoFear's IAP hack and edit the quantity value through pointer hack if you already have an item with a large amount. If you don't, you can use the old inbox hack method to make one simple stack 500m and use that pointer as reference. NoFear replied to you already, mate. Locate exp value, and replace with a low value quantity address. You can get one from your inbox or inventory very easily. Which methods are you trying? You can only hack gold through IAP hack. He made a 20 wood stack into a lot of M16 but you can stop whenever you want. Or repeat as many times you feel necessary. Screenshot your price list because of currency. Values in double, from last to first, grouped. You can also single search this.

Guys I want to buy modified weapon box but cannot find it via group search so I can use NoFear's gold hack method... What can I do?

You only do one search. What do you mean search 20 times? You do one group search like 640;680::100 and look for the right address. Mate, get DU Recorder and send me a clip please.. What do you mean? Don't do this like a shot in the dark, I'll break your legs.

some times the two items fresh from buying needs a restart of game before doing searches again. some time too searching group address is not possible I had a case like that. couz they have different adresses location. but you could still try the old single value search and add instead of replace. but most likely the group search of @Krakken's tutorial is better to find and add value to 500000000 only dont exceed. goodluck hope it will save for u now. try buying new resource and restart then search it again _______________________________________________ added 2 minutes later the above one is correct follow @NoFear tutorial

With everything as the video? Have you tried with different values? Like instead of 640 trying with 580? Grouping two consecutive items in 100-size group? Did you do exactly like the video? Free space in inventory and quantity set before restart? There is no refining in this hack. And finally, after edit when you take the items out does the wood/stone even change to the value you set, or does it go down as normal? This is pertinent info to make sure everything you're doing is right.

Post screenshots of your address list. The idea, if you don't have a 500m stack or a big number previously edited, is to work with an unchanged group of different values. For that I used the example of a 640 and a 680 stack, spawned one after the other. Work with different numbers. If you're getting too many results, look for another value: remove some of them and try again after a fresh restart. I don't do this hack with refining. That ALWAYS crashed my game. You can do this in one shot with one search and one edit. Keep your inbox organized. So you want a lot of modded AKs. Once you get one, clean your inbox so it's easily located. Example by order in inbox: - 700 wood - 700 stone - 1 Modded AK - 70 gas. This way it's not messy with a lot of 1D values. At least while you're not nailing it. For that, clean your inbox carefully before doing anything! When you reduce the wood/stone value, make them different from each other, preferably by 40 or so values. Then there are a few possible outcomes from that list which you can witness in the video (# = random number) ####D ##D yourvalue D ###D This is a completely unrelated set. Ignore it. -1#########D 0D yourvalue D 0D -1#########D Not this one either although it will seem coherent with the values in your inbox. Finally: -1#########D 0D Verification D yourvalue D 0D -1#########D This is the correct one. Select both the quantity and verification, press edit. Tick "add to value, do not replace". Type 500000000. Click OK. Take one item from that stack (in case of stone and wood you'll see immediately the value jumping to 500m) and restart to check. How can I help? Can you record a clip? I am not having much time but I'll help as I can.

Thanksssss! Anonymous was already check marked...and all of my results still show up as Ca, any ideas? Lmfao, I just had to search in a bigger group to find the anonymous ones, silly me.

Dang it I cannot spawn the bars... After group search (300;100;300;100) it shows only four options and after going to 300 it shows these which I cannot figure out what to choose to proceed cause it's different from NoFear's vid. If anyone could help I'd be greatful! This is the only GG trick that I cannot get through till now...

Help with pointer hack I've correctly followed your steps way through saving dword value of pointer in gold but after that when i search for exp boost price "900;550;250" in double nothing shows what did i do wrong. And yes I'll be honest your vid was so fast it kinda felt like you didn't want us to understand a bout it but you were just making it fit from that 10mb max size of attachmemt file. Btw thanks hope you can help me

@NoFear I saw video Metal bar hack and can i ask about number 25 in group search. What is it, what it mean?

Wew, the 250 isn't coming up for me... 900;550 works but once I add 250 in the group search, nada EDIT: Managed to make it work by editing other values instead. Thanks @NoFear

I was hoping we could brute force gold the same way, but we can't. For those with unhacked gold must follow @NoFear Not the correct address mate, try to search for that value alone since it's huge. You should get 6 results tops. Should be in the top 3, and should be the one with a verification address similar to that value directly above. If you watch the video, I come across the set you're in. Keep searching. The grouping method is only for those whose inboxes were still virgins. Yours has lost it a long time ago

please explain, i tried to follow step by step, but since my game is in hong kong dolloar currency, i changed the search to 798hkd instead of 99.9usd on the initial group search. followed all the steps to the point when nofear searchs for the 900;550;250 xp search , then thaz when i have no results come up.

Okay guys, I think I know what's going on and why you can't inbox edit. I've recorded a video and I'm uploading. Things to keep in mind: 1. This can be done from scratch. All you need is gold and gameguardian. 2. You must have open slots in your inventory. And I mean after the fresh restart. Not "I remembered halfway so I'll do it now". 3. You must group two consecutive items in a row, preferably two big numbers that aren't hundreds. Like buy a couple 700x stone stacks and make them 680/640 or whatever. 4. Find the addresses where there's a verification address. Select BOTH Dword and for the quantity value and verification value and [add to value] 500,000,000 for instance. 5. Remove one time the item from that stack, close game. Check for profit. Once you nail it, apply the same procedure for weapons. Remember! The first and only thing you can and will do in game will be editing the value before you take it out. Anything not involving that will crash. The idea is to narrow down this value without refining. Two consecutive items in a row is searchable with a group value of 100. Video soon!

just do the group value serch like we did in chopper hack ( i don't know the acid bath's 7-8-9-10 value ) and in result go to the value and cheak all value which u edited to hack the acid bath edit it with zero and restar the game like we does i have problem to in the chopper by editing this vaue to zero i was able to get my chpper back try it .... after that don't complete the acid bath again cause i think it's not in the game right now so

Here you go. Remember to back up you previous save first just to be safe and because it's good practice. NOTE: all items in the inbox are in the 1bill range for stack size so pull as many as you want. zombie.survival.craft.z_v1.5.5.zip

Bypassing XOR encryption in mobile games with Game Guardian In the last few months we noticed increased number of mobile games that uses some sort of encryption. Some of them are simple, like multiplying value with some random number (example: let’s say random number is 8 – in that case, 10 gold in our in-game inventory will be stored as 80 in memory). This simple kinds of encryption can’t trick anyone. But XOR encryption is different story. It is one of the simplest encryption methods, but in most cases it can’t be broken (if data and key have the same length). It is often used as a part in more advanced ciphers. But we will cover this latter. There are lot of tutorials that teach us how to bypass XOR encryption in mobile games, but most of them don’t show us process that lies behind. So before we start, we need to read some theory about the subject. If you learn this, you will be able to bypass XOR encryption with only basic memory editor, paper and pen. Of course, this is some sort of advanced tutorial – we assume that you are at least familiar with basics of memory editing. Cryptography 101 (logic for dummies) In the beginning, there was Boolean algebra. For those who haven’t overslept math and logic classes, you can skip this chapter. If you have overslept, read carefully. George Boole was mathematician, logician and philosopher who published his most famous notes in the middle of the 19th century. You probably asked yourself why are you reading about some dude who lived 100 years before ENIAC. This dude is father of all computers – every digital circuit on our planet works on his principles. For our story, it is important to notice that every algebra has own values and operations. Imagine that, in some sort of simple algebra, values are set of natural numbers from 1 to 10 [1,2,3,4,5,6,7,8,9], and only operations are addition(+), subtraction(-), multiplication(*), and division(/). From our knowledge of elementary algebra (math from school), you can tell that 1+1 =2, or 2*4=8. While elementary algebra deals with numbers, Boolean algebra use only two values – TRUEand FALSE. They are represented as 1(true) and 0(false). All operations are done on this two values. Of course, you can’t preform multiplication or subtraction on this values. We need some other operations that can be preformed on TRUE and FALSE. These operations are called bitwise operations. There are three basic operations in Boolean algebra – NOT(¬), AND (∧) and OR (∨), and they are really simple to understand. Take a look at this image, and everything will be clear. Source: Wikipedia Just kidding, forget this and let’s move on. Basic bitwise operations I know this will maybe be hard to understand, especially if this is your first time you read about logic. So I will try to make it simple. Boolean algebra (and any other logic) are made to teach us how to make correct conclusions. In elementary algebra, correct conclusion is when we write that 1+1=2. As we said, in Boolean algebra there are only two values, and we can only preform operations on them. Now imagine that we have a few true or false statements: Tom is a cat (TRUE or 1) Jerry is a mouse (TRUE or 1) Sky is green (FALSE or 0) NOT operator This is fairly simple examples. Let’s see our first operator, NOT(¬). “Tom in not a cat”, is this statement true or false? Of course, it is FALSE. Jerry is not a mouse = FALSE or 0. Sky is not green = TRUE or 1. This operator preforms logical negation on a given statement. 0 become 1, and 1 become 0. We can write it like this: ¬0 = 1 ¬1 = 0 AND operator AND(∧) operator takes two arguments, and returns TRUE only if both arguments are TRUE. Tom is a cat AND Jerry is a mouse = TRUE(1). Tom is a cat AND Sky is green = FALSE(0). You can easily remember this operator – just multiply two arguments and you have correct result. We can write it like this: 1 ∧ 1 = 1 1 ∧ 0 = 0 0 ∧ 1 = 0 0 ∧ 0 = 0 OR operator OR (∨) operator takes two arguments, and return FALSE only if both of the statements are FALSE. In every other case it returns TRUE. Tom is car OR Sky is green = TRUE(1). Sky is green OR Sky is red = FALSE(0). 1 ∨ 1 = 1 1 ∨ 0 = 1 0 ∨ 1 = 1 0 ∨ 0 = 0 Maybe you wonder why are we talking about Tom and Jerry. In computer world, everything is made in binary system. There are only two states in computer – there is current flow (1) and there isn’t current flow (0). So every information is stored in binary numeral system. Each digit (0 or 1) is called bit. Group of 8 bits are called byte. Any information can be translated into binary system. So our “tom” will be 01110100 01101111 01101101 in binary, and “sky” will be 01110011 01101011 01111001. Guess what? You can preform this bitwise operations on binary values. So, “tom” OR “sky”? 01110100 01101111 01101101 tom ∨ 01110011 01101011 01111001 sky ____________________________ 01110111 01101111 01111101 wo} If we want preform AND operator, this will be result: 01110100 01101111 01101101 tom ∧ 01110011 01101011 01111001 sky _______________________________ 01110000 01101011 01101001 pki Well, this was not very useful. But it is important to remember this, because now you will learn another bitwise operation – exclusive disjunction (exclusive OR, known as XOR). XOR (exclusive OR) bitwise operator I hope you understand these basic bitwise operators. There is also so-called “secondary operators or operations”, which can be derived from basic operators. One of these secondary operators is XOR, or exclusive OR. You will understand why is it called “exclusive OR” when you see the following table. 1 XOR 1 = 0 1 XOR 0 = 1 0 XOR 1 = 1 0 XOR 0 = 0 As you can see, if you perform XOR operation on two different values, it will return 1 or true. If values are the same, it will return 0 or false. So what is the catch? Why are XOR so special, and why is it used in cryptography? Now, look again our previous example, and you will see. From now on, we will preform XOR operation on original data (“tom” in our case) with the key (“sky” in our case). 01110100 01101111 01101101 tom XOR 01110011 01101011 01111001 sky _____________________________________ 00000111 00000100 00010100 //this can't be converted to meaningful text But what will happen if we XOR out new value (00000111 00000100 00010100) with the same key (sky or 01110011 01101011 01111001)? Let’s try it. 00000111 00000100 00010100 XOR 01110011 01101011 01111001 sky ___________________________________ 01110100 01101111 01101101 tom Right, we got our original data. But there is more -what if we don’t know the key (“sky”) 01110100 01101111 01101101 tom XOR 00000111 00000100 00010100 ___________________________________ 01110011 01101011 01111001 sky We have out original key. This is the reason why XOR operator is special. We can’t achieve this with other operators. XOR encryption in mobile games So let’s see some real world example – using XOR encryption in mobile games. Imagine that you have 1000 gold in some game. Developers implemented that all values are XOR-ed with the key 1337, and stored in memory. So look at the example. For conversion for decimal to binary you can use Windows calculator, or some online tools [BINARY TO DECIMAL CONVERTER] 0000001111101000 1000 XOR 0000010100111001 1337 _________________________ 0000011011010001 1745 This means that “1000” gold is stored as “1745” in memory. If you earn more gold (let’s say you got 1050 gold now), it will be stored in memory like this. 0000010000011010 1050 XOR 0000010100111001 1337 _________________________ 0000000100100011 291 So how we can bypass this sort of encryption? Bypassing XOR encryption with Game Guardian We already saw that: original value XOR key = encrypted value encrypted value XOR key = original value original value XOR encrypted value = key With this principle, we can bypass XOR encryption even if we don’t know that key developers used. So let’s start with practical work. If you aren’t familiar with fuzzy search, it will be useful to first read this tutorial [GAME GUARDIAN FUZZY SEARCH TUTORIAL]. We are going to use examples from previous paragraph. Our first step is to find address where the encrypted value is stored. This step is simple. First, scan for unknown starting value – this is done by selecting Fuzzy search from Game Guardian. As value type, you can choose DWORD (it was DWORD in all games that we cheated). Change the amount of gold in-game, then search for changed value. Repeat this step until only one address has left on the list. Now it is time to check if XOR encryption is used. Let’s say you got 1000 gold in game, but with fuzzy search you found value 1745. Preform XOR operation on this two values. 0000001111101000 1000 //Ingame gold XOR 0000011011010001 1745 //Value that you have found with fuzzy search _________________________ 0000010100111001 1337 //Key? --write it down Now change original value – earn or spend some gold. Let’s say you have 1050 gold now. Look at the address that you found with fuzzy search, and read the value. Again, preform XOR operation with in-game value and in-memory value. 0000010000011010 1050 //In-game value XOR 0000000100100011 291 //Value which is stored in memory _________________________ 0000010100111001 1337 //KEY!! If two keys are the same, XOR encryption is used and you have found the key. If they are not, XOR encryption is not used. Now, let’s change our gold (it was our primary goal, right?). We want 9999 gold. Again, preform XOR operation on it with key that you found (1337 in our case). 0010011100001111 9999 XOR 0000010100111001 1337 ___________________________ 0010001000110110 8758 Change the value that you found with fuzzy search – as new value set 8758. Open game again, and you should have 9999 gold. You can now cheat game using paper and pen, as we promised on the beginning. But it would be smarter if you use XOR calculator built in Game Guardian Second method to bypass XOR encryption Now, you will see the true power of Game Guardian. For this method, it is important to note that in most games, encrypted value and key are stored next to each other in memory – for DWORD type,one value occupies 4 bytes,so the key is usually 4 bytes away from encrypted value. Look at this picture. In Game Guardian, there is builtin method which automatically search for values, and XOR them with value which is X bytes away. That means that we don’t need to do fuzzy search, or calculate XOR values. Game Guardian can do it for us. Let’s get back to our previous example and imagine that encrypted value and key are 4 bytes away. If you have 1000 gold in-game, click on Known search, as type choose Dword (it can be some other types too, but it is usually dword.). As value, put in 1000X4, and click on search. In this example, first number “1000” is amount of currency that we want to change. Second part, “X4“, marks how many bytes away is the key. For dword values it can be X4,X8, X12, X16… Earn or spend some currency – let’s say that you have 900 gold now. Now input 900X4, and click on refine. Repeat previous step until you have only one address left (or few addresses if you want). Click on Edit, and as a value input 9999X4. And that’s it. Game Guardian will automatically search for encrypted values, and XOR them with key which is X bytes away. Pretty impressive feature. With this, our tutorial has finished. There will be reference links bellow, if you want to know more about this subject. Any suggestions are appreciated. Happy cheating. Reference links [Algebraic operation – Wikipedia article] [Binary numbers] [Boolean algebra] [Exclusive OR – XOR, Wikipedia] [NoFear’s tutorial – Xor search guide] [Binary to decimal online calculator]

ok done yeh i try the group value and done that zero which i edit

No luck for me to group search the traders required ingredients , has anyone tried? I thought if I find those I might be able to find the address of the crates