random xor Lua change value

[Rs92ks]

kk1=1890
gg.clearResults()
gg.setRanges(32)
gg.searchNumber(kk1..'x4',4)
hk=gg.getResults(999)
for _,p in ipairs(hk) do
  p2=({address=p.address+0x4,flags=4})
  if
    p2.value==1 then
    p.value=99999 gg.setValues(hk)
  end
end

Help. Value with random xor key. My script changing to value=value. How to fix?

[Enyby]

27 minutes ago, Rs92ks said:

p2.value==1

Never true, because you create table without value.

Maybe you forget call getValues.

[added 3 minutes later]

kk1=1890
gg.clearResults()
gg.setRanges(32)
gg.searchNumber(kk1..'x4',4)
hk=gg.getResults(999)
hn=gg.getResults(999)
for _,p in ipairs(hn) do
  p.address = p.address+0x4
end
hn = gg.getValues(hn)
for i,p in ipairs(hk) do
  if hn[i].value==1 then
    p.value=99999
  end
end
gg.setValues(hk)

 

[Rs92ks]

Works