Counting amount of times a value appears in table

[nok1a]

I want to have script that takes table from the result list. Then prints out the amount of times a value appears. If the value has already been counted once it must continue to the next index. I have this script but it also counts the values that already have been counted.

local count = {}
local t = {}
gg.searchNumber("3D;8D;4D::17", gg.TYPE_DWORD) -- random search
count = gg.getResultsCount()
t = gg.getResults(count)
for i = 1, #t do
  loop = 0
  for b, w in ipairs(t) do
    if t[i].value == w.value then
      loop = loop + 1
    end
  end
  print(t[i].value, loop)
end

 

[BadCase]

15 hours ago, nok1a said:

I want to have script that takes table from the result list. Then prints out the amount of times a value appears. If the value has already been counted once it must continue to the next index. I have this script but it also counts the values that already have been counted.

local count = {}
local t = {}
gg.searchNumber("3D;8D;4D::17", gg.TYPE_DWORD) -- random search
count = gg.getResultsCount()
t = gg.getResults(count)
for i = 1, #t do
  loop = 0
  for b, w in ipairs(t) do
    if t[i].value == w.value then
      loop = loop + 1
    end
  end
  print(t[i].value, loop)
end

 

If I understand correctly and you want it to print out the total number of times a value appears then this should work.

 

local count = {}
local t = {}
gg.searchNumber("3D;8D;4D::17", gg.TYPE_DWORD) -- random search
count = gg.getResultsCount()
t = gg.getResults(count)
local totalsTable = {}
for i,v in pairs (t) do
    if not totalsTable[tostring(v.value)] then
        totalsTable[tostring(v.value)] = 1
    else
        totalsTable[tostring(v.value)] = totalsTable[tostring(v.value)] + 1
    end
end
print(totalsTable)--totals of all values
print(totalsTable["8"])--totals of specified value, make sure you put it in quotes so it is treated as string

 

[nok1a]

Working perfect.