Need help making a script to edit each value

[TisNquyen]

I have tried many times but can not find the value, if found also can not edit, so I need help from you

 

 

 

 gg.setVisible(false)
gg.searchNumber('0.8;1.9;3.25', gg.TYPE_FLOAT)
local results = gg.getResults(100) 

for i, v in ipairs(results) do
         if v.value == '0.8' then
             v.value = '1.49'
  elseif v.value == '1.9' then
             v.value = '2.4'
  elseif v.value == '3.25' then
             v.value = '3.59' end
end

gg.setValues(results)

while true do 
  if gg.isVisible() then
      break
    else
      gg.sleep(100);
    end
end

os.exit()

Edited June 16, 2018 by TisNquyen
Misspell

[Enyby]

3 hours ago, TisNquyen said:

gg.searchNumber('0.8;1.9;3.25', gg.TYPE_DWORD)

Dword can not be fractional.

[TisNquyen]

8 hours ago, Enyby said:

Dword can not be fractional.

I'm sorry for the wrong writing, but I still need your help

gg.searchNumber('0.8;1.9;3.25',gg.TYPE_FLOAT)

[Enyby]

1 hour ago, TisNquyen said:

I still need your help

I do not see what.

12 hours ago, TisNquyen said:

if v.value == '0.8' then

You need read about float and it precision. Possible this compare not work. Try use number, not string.

Also maybe it not work too. In general compare for equal fractional values is bad idea.

It is known issue with fractional values. So you can use Internet for search solution. For example: http://lua.2524044.n2.nabble.com/Float-numbers-equality-td7651382.html

[TisNquyen]

5 giờ trước, Enyby nói:

I did not found.

You need to read about phao and precision. This comparison is not work. Try to use number, not a string.

Cũng có thể nó cũng không hoạt động. Nói chung so sánh các giá trị phân số bằng nhau là ý tưởng tồi.

Nó được biết đến vấn đề với các giá trị phân đoạn. Vì vậy, bạn có thể sử dụng Internet cho giải pháp tìm kiếm. Ví dụ: http://lua.2524044.n2.nabble.com/Float-numbers-equality-td7651382.html

I still do not understand!

Can you guide me in detail?

[Enyby]

@TisNquyen I can not go the way for you. You must go through it yourself.
In short, fractional numbers should be compared approximately like this:

if math.abs(x - 3.4) < 0.00001 then -- here compare x with 3.4
  -- do something if x equal 3.4
end

 

[TisNquyen]

17 minutes ago, Enyby said:

@TisNquyen I can not go the way for you. You must go through it yourself.
In short, fractional numbers should be compared approximately like this:

if math.abs(x - 3.4) < 0.00001 then -- here compare x with 3.4
  -- do something if x equal 3.4
end

 

Thank you! You do not understand this, I do not understand. Because I do not understand high education. So do not understand, whether you reply to me

Thank you!

[Enyby]

@TisNquyen I wrote you all above. Even the link gave. Do not be so helpless - try yourself to look for information on the Internet. This is done very simply.

[TisNquyen]

39 minutes ago, Enyby said:

@TisNquyen Tôi đã viết tất cả các bạn ở trên. Ngay cả liên kết đã cho. Đừng quá bất lực - hãy thử tìm kiếm thông tin trên Internet. Điều này được thực hiện rất đơn giản.

Without the script template, nothing is simple

[Enyby]

@TisNquyen This is not true. Learn lua. Learn to use the search on the Internet and you will not need templates.

[TisNquyen]

Cách đây 14 phút, Enyby đã nói:

@TisNquyen Điều này không đúng. Tìm hiểu lua. Tìm hiểu cách sử dụng tìm kiếm trên Internet và bạn sẽ không cần mẫu.

Sorry! I'm a beginner in scripting so I do not understand much and have tried many ways, but many places do not have a place to guide.

Since and I recently posted this article to ask if anyone was guiding me, but still have not found a good answer, I am very disappointed!

[Enyby]

@TisNquyen This is not a school, or a kindergarten. This is the Internet. No one will nurse you. You must train yourself. There is enough information on the Internet for this. It's silly to expect that someone will teach you on the Internet.
If you are not able to learn by yourself - hire a tutor who will teach you and to whom you will pay money.

[TisNquyen]

OK! Thank You