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About Kimiice7

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    8.x (Oreo)
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    Redmi Note5

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  1. I've did trial to search summon cost for gdi harvester.. From 60 to 0, I found the value.. Its works for custom vs bot.. But when i tried on ranked, the system detected missmatch.. I won but the history and replay showed that i lose.. But i don't know some how in one match system did not detecting the result.. And i won, i try to repeat the proccess but fail.. I believe in expert coding this game was hackable.. I really want to find the vision range.. But not yet found it.. In my opinion.. Reveals vision of full map is the only hack with no affect on match results.. Just like radar map on mobile legends.. Its can do without problems.. But when you hack diamond, damage, or other statistic.. The server will detect the missmatch.. Any expert to help to do this?
  2. The form like this was out of my knowledge.. But when i see this.. I can get it, Where i can learn more about scripting language like this? Anyway.. This forum really helpfull to help people like me who want to learn more about lua scripting. Thanks alot..
  3. Thanks brother.. For your help, Will try on my real codes now..
  4. Help me to build this script.. gg.setRanges(gg.REGION_C_ALLOC) gg.searchNumber('0;1;2:', gg.TYPE_DWORD, false, gg.SIGN_EQUAL, 0, -1) gg.refineNumber('0', gg.TYPE_DWORD, false, gg.SIGN_EQUAL, 0, -1) --for information, i need to edit 100 items-- --t[1], t[1].address +150, t[1].address +300, t[1].address +450, ..etc.-- --I already know the pattern is t[1].address +(150*n)-- --its for edit first item-- t = gg.getResults(5) for i, v in ipairs(t) do t[1].value = 99 end gg.setValues(t) --here the problem -- --QUESTION : how to edit 2nd item untill 100th item in one command?-- for i, v in ipairs(t) do t[1].address = t[1].address +150 t[1].value = 99 --edit 2nd item-- end gg.setValues(t) --its waste time to edit it one by one untill 100th item-- --i did some trial and error to edit all of them in one shoot-- --like n = (1~100) , t[1].address = t[1].address + (150*n)-- --but fail, i tried on gg.alert(1~100) its show alert 101, i feel stupid -- -- I TRIED TO SEARCH REFERENCES FOR THIS,-- --READ Some guide on this web, but not yet found the answear.-- gg.alert('THANKS FOR HELPING ME ') Help Set Multiple Values.lua
  5. I can't use third methode.. Because the real table i have they not contain the squennced numbers like 10,20,30 Anyway.. Thanks for show me some defferent methode.. Its usefull to improve my kowledge and my skill.. Thanks bro.. Appreciate this..
  6. Thanks man.. This is exactly what i want to do but i don't know how to make it.. You gave me a simple and clear explaination.. And the example make it perfect.. Thanks alot.. Really appreciate.. [sorry have bad english]
  7. Please help me how to make group search like this r = gg.prompt({'LEVEL [1;5]'},{1},{'number'}) p = {'10','20','30','40','50'} --bad list-- if r[1] == '1' then rp = p[1] end if r[1] == '2' then rp = p[2] end if r[1] == '3' then rp = p[3] end if r[1] == '4' then rp = p[4] end if r[1] == '5' then rp = p[5] end gg.searchNumber(r[1]..';100;'..rp..';1000:', gg.TYPE_DWORD, false, gg.SIGN_EQUAL, 0, -1) --How to call rp in group search without making bad list..??-- --Because i have 100 items in table p{} -- -- for p[x] , how to set x= r[1] ?? -- -- i tried this -- --gg.searchNumber(r[1]..';100;'..p[r[1]]..';1000:', gg.TYPE_DWORD, false, gg.SIGN_EQUAL, 0, -1)-- --also tried x = r[1] then call p[x] but didn't work-- --Thanks for your help guys-- help variable gg.prompt.lua
  8. help gg.prompt.lua Qjctx = 1 if gg.isVisible(true) then gg.setVisible(false) end function main() n = gg.prompt({M='value1',N='value2'},nil,{'number','number'}) if n == nil then os.exit() end if n.M and n.N then A() end end function A() gg.clearResults() gg.searchNumber(n.M..';'..n.N, gg.TYPE_DWORD) gg.clearResults() gg.alert(n.M.. '+'..n.N..'='..(n.M+n.M)) end main() while true do if gg.isVisible(true) then gg.setVisible(false) Qjctx = 1 end gg.sleep(100) if Qjctx == 1 then main() end end Please help me fix this For example i do search value1 = 4 and value2 = 4 First search work fine.. But when i try to do second search i got this error.. After restarting script its work again.. And always second action got error.. Thanks for your help..
  9. Is this work on ranked?
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