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How To Freeze the Value Of The 2 Value Can You Help Me To Fix This


SHANNPROGAMING

Question

gg.searchNumber("600;256;0:9", gg.TYPE_DWORD, false, gg.SIGN_EQUAL, 0, -1, 0)

gg.getResults(4)

gg.refineNumber"256;0", gg.TYPE_DWORD, false, gg.SIGN_EQUAL, 0, -1, 0)

gg.getResults(3)

revert = gg.getResults(100, nil, nil, nil, nil, nil, nil, nil, nil) 

local t = gg.getResults(100, nil, nil, nil, nil, nil, nil, nil, nil)

for i, v in ipairs(t) do

 if v.flags == gg.TYPE_DWORD then

  v.value = '"-999,999,999;0"'

  v.freeze = true

 end

end

gg.addListItems(t)

t = nil

    end

 

--------------------------------

How To Freeze the Value Of

gg.refineNumber"256;0", gg.TYPE_DWORD, false, gg.SIGN_EQUAL, 0, -1, 0)

 

I Can't Freeze The Value Like This

revert = gg.getResults(100, nil, nil, nil, nil, nil, nil, nil, nil) 

local t = gg.getResults(100, nil, nil, nil, nil, nil, nil, nil, nil)

for i, v in ipairs(t) do

 if v.flags == gg.TYPE_DWORD then

  v.value = '"-999,999,999;0"'

  v.freeze = true

 end

end

gg.addListItems(t)

t = nil

    end

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1 answer to this question

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You forgot to add the ( 

In gg.refineNumber

And in it should be like that

v.value = "-999,999,999;0"

And delete the last end

gg.searchNumber("600;256;0:9", gg.TYPE_DWORD, false, gg.SIGN_EQUAL, 0, -1, 0)

gg.getResults(4)

gg.refineNumber("256;0", gg.TYPE_DWORD, false, gg.SIGN_EQUAL, 0, -1, 0)

gg.getResults(3)

local t = gg.getResults(3, nil, nil, nil, nil, nil, nil, nil, nil)

for i, v in ipairs(t) do

 if v.flags == gg.TYPE_DWORD then

  v.value = "-999,999,999;0"

  v.freeze = true

 end

end

gg.addListItems(t)

t = nil

And that all your problems i think 🤔

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