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phpdev

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  1. i got this msg local login = "http://localhost.php" unexpected symbol "i"
  2. i know how to using PHP as i just make it basic <? echo "login" ?> then i will change it on future but i am now trying to work on LUA how i can fix it
  3. i will exploit to you print('FULL: ', gg.makeRequest('http://xxxx.com/php/php.php')) function right() gg.alert("login done") end function wrong() gg.alert("can't login") os.exit(); end if gg.makeRequest == "login" then right() else wrong() end i will like to doing this but i made this not working by my self so http://xxxx.com/php/php.php here data is "login" getting this from .php login if its not login showing on php that means not working and exit from the script
  4. Hello, i have created script ,lua and i would like linked this with website php or html checking for example the code is ***** if menu1 == 1 then A() end if menu1 == 2 then B() end if menu1 == 3 then C() end if menu1 == 4 then D() end if menu1 == 5 then Exit() end ***** and to start the code should be first checking with my webite like "http://*****.com/xx.php" if i have add source on website "1" the script is open and show in script "login" if i have change it my website to "0" unlogin try again script not open and end print('GET 4: ', gg.makeRequest('https://localhost.com/login.php', {['User-Agent']='My BOT'}).content) same as this coded but i need including function right() gg.alert("1") end function wrong() gg.alert("0") os.exit(); geting the number from the website i need help could you help me
  5. print('GET 4: ', gg.makeRequest('https://localhost.com/login.php', {['User-Agent']='My BOT'}).content) same as this coded but i need including function right() gg.alert("1") end function wrong() gg.alert("0") os.exit(); geting the number from the website i need help
  6. Hello, i have created script ,lua and i would like linked this with website php or html checking for example the code is ***** if menu1 == 1 then A() end if menu1 == 2 then B() end if menu1 == 3 then C() end if menu1 == 4 then D() end if menu1 == 5 then Exit() end ***** and to start the code should be first checking with my webite like "http://*****.com/xx.php" if i have add source on website "1" the script is open and show in script "login" if i have change it my website to "0" unlogin try again script not open and end could you help me also i found lua someone linked with his website script https://www110.zippyshare.com/v/EfgEpwl6/file.html could you help me
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