[LUA scripting]

Thanks. This is the simple script I am trying to put together. I apologize if it's messy, it's literally the first one I have ever done based off of what I have been reading here. The first menu choice and last menu choice work fine, it's the 2nd menu choice I am trying to get working correctly. When you search for 1.85 you get 3 results and I need to edit just the 2nd one and change to 99999, as I mentioned. Is this correct? (I copied it from the gg Class Reference guide):

menu=gg.choice({'+99999% Gear & Gun','+99999% Gear only', '+100% Damage only'})
    if menu==1 then
        gg.searchNumber('1.85',gg.TYPE_FLOAT)
        gg.getResults(100)
        gg.editAll('99999',gg.TYPE_FLOAT)
    gg.alert('Equip +85% Camo and Decal and enjoy!')
    end
if menu==2 then
        gg.searchNumber('1.85',gg.TYPE_FLOAT)
        gg.getResults(3)
        r[2].value='99999'
        print('Edited:',gg.setValues(r))
    gg.alert('Equip +85% Decal and enjoy!')
    end
if menu==3 then
        gg.searchNumber('1.35',gg.TYPE_FLOAT)
        gg.getResults(500)
        gg.editAll('2',gg.TYPE_FLOAT)
    gg.alert('Equip +35% Camo and enjoy!')
    end

 

[LUA scripting]

Trying to write a simple script and this tutorial has been very helpful. My question is similar to the one asked above but I didn't quite understand the answer.  I am doing a Float search for a number (1.35) and GG comes up with 3 results every time. I only need to edit/change the 2nd out of 3 results. EditAll does not work because it edits all of them (obviously). How would I specify the 2nd result for editing? editResult(2) or something along those lines?  Thanks for the help.