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  1. 4 points
    for _=1, #Menu - 0.5 do if _ % 2 == 1 then -- ... end end is identical to for _ = 1, #Menu - 0.5, 2 do -- ... end but second option is more effective and clear.
  2. 4 points
    Watch on YouTube: 73.0: Formula calculator - GameGuardian
  3. 3 points
    Have you tried it at least? I highly doubt that searching for 500 consecutive addresses and editing all of them to one value can noticeably slow down your script. So are you sure that it does not suffice because of performance reasons? As pointed out above, editing values one-by-one in a loop is very inefficient. This approach should be used instead, if simple one with fuzzy search does not suffice: Example of implementing it: local startAddress = 0x12340000 local count = 500 local editValue = '555444' local values = {} for i = 1, count do values[i] = {address = startAddress; flags = gg.TYPE_DWORD; value = editValue} startAddress = startAddress + 4 end gg.setValues(values)
  4. 2 points
    x = gg.prompt({"Enter Value"}, nil, {"number"}) if x == nil then gg.alert("Canceled") end s = "1;3;2;"..x[1].."000~"..x[1].."999;0::70" gg.searchNumber(s, gg.TYPE_DWORD, false, gg.SIGN_EQUAL, 0, -1) f = gg.getResultCount() gg.alert("We found: "..f)
  5. 2 points
    Name of Game: The OutlivedPlay Store Link (If it's a paid app, the apk): https://play.google.com/store/apps/details?id=com.herogame.gplay.theoutlived&hl=enVersion: 1.0.11What cheat? Health, xp, gold...: AnythingHave you tried cheating this game? No
  6. 2 points
    You can subscribe to our new videos. Watch on YouTube: How to speed up search - GameGuardian
  7. 1 point
    Sorry. Distracted with other games. Working on this one: https://play.google.com/store/apps/details?id=com.dle.afterpulse
  8. 1 point
  9. 1 point
  10. 1 point
    This problem was solved many times, you can use search box to find solution before asking. But this is the fix *Sorry fot bad English gsearch.lua


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